Chart Control - How to use SetDashArray in ChartLineStyle

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How to use SetDashArray in ChartLineStyle

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Category: Codejock Products
Forum Name: Chart Control
Forum Description: Topics Related to Codejock Chart Control
URL: http://forum.codejock.com/forum_posts.asp?TID=19539
Printed Date: 22 November 2024 at 10:39am
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Topic: How to use SetDashArray in ChartLineStyle

Posted By: SimasJ
Subject: How to use SetDashArray in ChartLineStyle
Date Posted: 01 March 2012 at 12:25pm

Hi,

I am sorry but I mistakenly posted this question in a different group. Here is the question:

I would like to create a series using a Dash style wider than the standard ones. I found the method SetDashArray in the ChartLineStyle object which appears to be what I need but I cannot find any documentation about it. Would you please provide an example of its usage?

Best Regards,

Jose Simas

Replies:

Posted By: SuperMario
Date Posted: 06 March 2012 at 1:19pm

DashArray you pass in an array with the pattern to follow. It can be as short or long as you like. It will follow the pattern you specify, if you specify 3 segments, then it will repeat those 3 segments. If you specify 1 segment, it will repeat this 1 segment. You must specify BOTH segment length and gap length or else you will get only a solid line.

For example, this is a little bigger than the standard dash:

xLineStyle.LineStyle.SetDashArray (Array(5, 2))

this is the pattern:

SetDashArray (Array(Segment1 width, first gap width, Segment2 width, second gap width, etc, etc))

These are also valid:

xLineStyle.LineStyle.SetDashArray (Array(2, 1, 5, 2))

xLineStyle.LineStyle.SetDashArray (Array(2, 1, 5, 2, 8, 3))

Here is code:

Dim xLineStyle As ChartLineSeriesStyle

Dim nThickness As Integer

nThickness = 5

Set xLineStyle = New ChartLineSeriesStyle

xLineStyle.LineStyle.DashStyle = xtpChartDashStyleCustom

xLineStyle.LineStyle.Thickness = nThickness

xLineStyle.LineStyle.SetDashArray (Array(5, 2))

Set ChartControl.Content.Series(0).Style = xLineStyle

Hope this helps

Posted By: SimasJ
Date Posted: 12 March 2012 at 3:52pm

Hi,

Thanks for the very clear explanation. Solved my problem completely.

Cheers,

Jose