[SOLVED] PropertyEnumItem index?

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I use code similar like this:
    Dim ItemEnum As PropertyGridItem

    'Adds a PropertyItemEnum item with a caption of "Enum" and an initial value of 2
    'This will cause the constraint with a value of 2 to be selected
    Set ItemEnum = Category.AddChildItem(PropertyItemEnum, "Enum", 2)

    'Adds some constraints along with a Data value
    ItemEnum.Constraints.Add "Windows 98", 1
    ItemEnum.Constraints.Add "Windows 2000", 2
    ItemEnum.Constraints.Add "Windows XP", 3

Now while ItemEnum is active, you can read the value of the selected item:

Debug.Print "Enum Item Value =" & ItemEnum.Value

So far so good. But how do i find this value later in the program?

The old VB method would be:

Value = cmbBox.ListIndex

to find the listindex of the currently selected item.

How do i find 'ListIndex' in PropertyGrid? lets say i selected Windows 2000, the listindex would be 2.

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rdeboer Members Profile Send Private Message Find Members Posts Add to Buddy List Groupie Joined: 29 April 2004 Location: Netherlands Status: Offline Points: 81	Post Options Post Reply Quote rdeboer Report Post Thanks(0) Quote Reply Topic: [SOLVED] PropertyEnumItem index? Posted: 06 January 2011 at 4:16pm
	I use code similar like this: Dim ItemEnum As PropertyGridItem 'Adds a PropertyItemEnum item with a caption of "Enum" and an initial value of 2 'This will cause the constraint with a value of 2 to be selected Set ItemEnum = Category.AddChildItem(PropertyItemEnum, "Enum", 2) 'Adds some constraints along with a Data value ItemEnum.Constraints.Add "Windows 98", 1 ItemEnum.Constraints.Add "Windows 2000", 2 ItemEnum.Constraints.Add "Windows XP", 3 Now while ItemEnum is active, you can read the value of the selected item: Debug.Print "Enum Item Value =" & ItemEnum.Value So far so good. But how do i find this value later in the program? The old VB method would be: Value = cmbBox.ListIndex to find the listindex of the currently selected item. How do i find 'ListIndex' in PropertyGrid? lets say i selected Windows 2000, the listindex would be 2.
	Product: Xtreme Suite Pro (ActiveX) version 11 Platform: Windows XP SP3 (32bit) Language: Visual Basic 6.0 SP6

Oleg Members Profile Send Private Message Find Members Posts Add to Buddy List Admin Group Joined: 21 May 2003 Location: United States Status: Offline Points: 11234	Post Options Post Reply Quote Oleg Report Post Thanks(0) Quote Reply Posted: 06 January 2011 at 4:29pm
	Same ItemEnum.Value will work later.
	Oleg, Support Team CODEJOCK SOFTWARE SOLUTIONS

rdeboer Members Profile Send Private Message Find Members Posts Add to Buddy List Groupie Joined: 29 April 2004 Location: Netherlands Status: Offline Points: 81	Post Options Post Reply Quote rdeboer Report Post Thanks(0) Quote Reply Posted: 06 January 2011 at 5:06pm
	How? I tried: Set Itemx = AdvancedGrid.FindItem("Enum") If Not (Itemx Is Nothing) Then Debug.Print Itemx.Constraints(Itemx.Value) End If But that gives an error? Excuse my stupidity :)
	Product: Xtreme Suite Pro (ActiveX) version 11 Platform: Windows XP SP3 (32bit) Language: Visual Basic 6.0 SP6

Aaron Members Profile Send Private Message Find Members Posts Add to Buddy List Senior Member Joined: 29 January 2008 Status: Offline Points: 2192	Post Options Post Reply Quote Aaron Report Post Thanks(0) Quote Reply Posted: 07 January 2011 at 1:36am
	Hi, Your stupidity is forgiven Constraints collection isn't zero based, first item will start at 1 So if you would add constraint: .Constraints. Add "First item", 0 .Constraints. Add "Second item", 1 .Constraints. Add "Third item", 2 and want to get the index of the first item, it will produce an error because there is no constraint with index 0 In this case you have to set Item.value + 1 Me.wndPropertyGrid.FindItem(ITEM.ID or "Caption").Constraints(Me.wndPropertyGrid.FindItem(ITEM.ID or "Caption").Value + 1).Data (or index) If you don't use successive numbers for the <Data> for the added constraints above doesn't work .Constraints. Add "First item", 0 .Constraints. Add "Second item", 1 .Constraints. Add "Third item", 2 .Constraints. Add "Third item", 4 .Constraints. Add "Third item", 8 In this case you have to loop constraints and compare constraint, annoying thing to do (in my opinion...) Best way is to start added constraint with <Data> = 1 and use successive numbers, this way you are able to use Item.Value to "find" selected constraint. Hope this helps
	Product: Xtreme SuitePro (ActiveX) version 15.0.2 Platform: Windows XP (32bit) - SP 2 Language: Visual Basic 6.0 Zero replies is not an option....

rdeboer Members Profile Send Private Message Find Members Posts Add to Buddy List Groupie Joined: 29 April 2004 Location: Netherlands Status: Offline Points: 81	Post Options Post Reply Quote rdeboer Report Post Thanks(0) Quote Reply Posted: 11 January 2011 at 10:33am
	Thank you again, Aaron!
	Product: Xtreme Suite Pro (ActiveX) version 11 Platform: Windows XP SP3 (32bit) Language: Visual Basic 6.0 SP6